 0 lessons
 0 quizzes
 10 week duration

Measurements
An introduction to numerical computation. Emphasis is placed on scientific and engineering notation, the rule of significant figures, and converting between SI and Imperial units.

Fractions, Percentage, Ratios and Proportion
Emphasis here is placed on understanding fractions, percent, and using ratios to compare quantities and set up proportions to solve problems.

Introduction to Algebra

Factoring

Solving Equations

Functions and Graphs

Geometry
This unit focuses on analyzing and understand the characteristics of various shapes, both 2D and 3D.
 Identify, measure, and calculate different types of straight lines and angles
 Calculate the interior angles of polygons
 Solve problems involving a variety of different types of triangles
 Calculate the area of a variety of different types of quadrilaterals
 Solve problems involving circles
 Calculate the areas and volumes of different solids
Factor a Difference of Squares
So far we’ve learned three factoring techniques. The first one, common factoring, is a technique that can be used for any polynomial. The other two were specific for quadratics, namely trialanderror and decomposition.
The whole purpose behind factoring any quadratic – if you haven’t discovered already – is convert it in such a format that enables you to solve for the x intercepts (the roots). A whole unit will be dedicated to solving equations, including first and second degree equation. Otherwise, if it’s in general form, you can’t easily do that.
You’ll find out here that some quadratics whose bterm is missing and whose a and c terms are being subtracted, can be factored by another technique known the difference of squares. Examples of quadratics that fit this pattern look like this:
 y = x² – 100 (easy)
 y = 98a² – 450b² (medium)
 y = (3x + 8)² – (x – 2)² (hard)
Also, as the name of the technique implies, both terms in the quadratic need to be perfect squares (squarootable).
Take equation (1) as an example. Taking the square root of x² yields x. In other words, √x² = x. Similarly, √100 = 10. In the second equation, after common factoring 2 from both terms, you get:
= 2(49a² – 225b²)
Notice now that √49a² = 7a and √225b² = 15b. Both terms within the parentheses are perfect squares; hence, this technique can be used.
In equation (3), the square root of (3x + 8)² is 3x + 8 and the square root of (x – 2)² is x – 2; therefore it fits the same mold. A summary of what’s required is written below.
Conditions required to factor a difference of squares:
 b term needs to be missing.
 The two remaining terms are being subtracted.
 The two remaining terms need to be a perfect square.
Let’s what a few examples: