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wrote...
Posts: 32
Rep: 2 0
6 years ago

Under the conditions of:
400 celsius degrees, 350 barr
We mix Nitrogen and Hidrogen at a rate of 3:1 (correspondly)
In equilibrium we get that 50% of the product is Amonia

N2 (g) + 3H2 (g) -> 2NH3 (g)

A) Calculate the equilibtium constant of pressure: Kp ?
B) Calculate the free Gibbs energy under that conditions? [Kj/mol]


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1 Reply
wrote...
6 years ago
Your expression is as follows: Kp= [NH3]2/[N2][H2]3

Gibbs Free Energy: {\Delta}G  =  {\Delta}H  -  T{\Delta}S

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