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 (Moderators: rulaman, mjs1973)
SakurasFlowers
wrote...
6 years ago
 How to write net ionic equations for basic and acidic solutions? How to write net ionic equations for basic and acidic solutions?Write a balanced net ionic equation for the following reaction in basic solution:1 ) Zn(s) + NO3- (aq) -> NH3(aq) + Zn(OH)4^(2-)Write a balanced net ionic equation for the following reaction in acidic solution:2 ) Mg(s) + VO4^(3-)(aq) -> Mg^(2+)(aq) + V^(2+)3 ) PbO2(s) + CI-(aq) -> PbCI2(s) + O2(g) Read 7790 times 2 Replies
wrote...
Donated
Valued Member
6 years ago
 Zn ------> Zn+2 & 2 electrons lost(NO3)- & 8 electrons taken ------> (NH4)+(N+5 in nitrate goes to N-3 in ammonium)four times the Zn reaction to balance the electrons taken & lost:4Zn ------> 4Zn+2 & 8 e-(NO3)- & 8 e- ------> (NH4)+combine the two 1/2 reactions:4 Zn & (NO3)-1 ---> 4 Zn+2 & (NH4)+1we need to balance the charges on both sides: -1 +9,....add 10 (OH-)'s to the right side & you will have 1- -1 :4 Zn & (NO3)-1 ---> 4 Zn+2 & (NH4)+1 & 10 OH-balance the H's using neutral water:4 Zn & (NO3)-1 & 7 H2O ---> 4 Zn+2 & (NH4)+1 & 10 OH-Also, here is a set-by-set way of doing them: http://tiny.cc/i0i6cyou can get answers or check answers to balanced redox reactions by going to this site!http://www.gregthatcher.org//Chemistry/BalanceChemicalEquations.aspx?StartsWith=O
wrote...
Educator
6 years ago
 Mg (s) + VO43- (aq) Mg2+ (aq) + V2+ (aq) (Base)Mg Mg2+ + 2 e-                 x33 e- + 8 H+ + VO43- V2+ + 4 H2O              x23Mg 3Mg2+ + 6 e-6 e- + 16 H+ + 2 VO43- 2 V2+ + 8 H2O3Mg + 16 H+ + 2 VO43- 3Mg2+ + 2 V2+ + 8 H2O + 16 OH-          on both sides3Mg + 8 H2O + 2 VO43- 3Mg2+ + 2 V2+ + 16 OH
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